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Q.

A thermodynamic process is shown fig. The pressures and volumes corresponding to some points in the figure are
PA=3×104Pa,VA=2×10−3m3 PB=8×104Pa,VD=5×10−3m3
In process AB, 600 J of eat is added to the system and in process BC 200 J of heat is added to the system. The change in internal snergy of the system in process AC
would be

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a

560 J

b

800 J

c

600 J

d

640 J

answer is A.

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Detailed Solution

Work done in process AB = 0
(∵isochoric process)
Work done in process BC
    =PBVC−VB=PBVD−VA =240J                    âˆµ isobaric process
Total work done dW = 240 J
dQ=600+200=800JdU=dQ−dW=800−240=560J
 

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