A thermodynamic process is shown in the following figure. The pressures and volumes corresponding to some points in the figure are:PA=3×104PaVA=2×10−3m3PB=8×104PaVD=5×10−3m3In the process AB, 600 J of heat is added to the system and in process BC , 200 J of heat is added to the system. The change in internal energy of the system in the process AB would be

No work is done along the path AB, because the process is isochoric.∴ Work done =PBVD−VA =8×1045×10−3−2×10−3=240J QAC=QAB+QBC=600+200=800J∴ (ΔU)AC=Q −W=800−240=560J

A thermodynamic process is shown in the following figure. The pressures and volumes corresponding to some points in the figure are:PA=3×104PaVA=2×10−3m3PB=8×104PaVD=5×10−3m3In the process AB, 600 J of heat is added to the system and in process BC , 200 J of heat is added to the system. The change in internal energy of the system in the process AB would be

No work is done along the path AB, because the process is isochoric.∴ Work done =PBVD−VA =8×1045×10−3−2×10−3=240J QAC=QAB+QBC=600+200=800J∴ (ΔU)AC=Q −W=800−240=560J

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A thermodynamic process is shown in the following figure. The pressures and volumes corresponding to some points in the figure are:
$\begin{array}{l} P_{A} = 3 \times 10^{4} Pa \\ V_{A} = 2 \times 10^{- 3} m^{3} \\ P_{B} = 8 \times 10^{4} Pa \\ V_{D} = 5 \times 10^{- 3} m^{3} \end{array}$
In the process AB, 600 J of heat is added to the system and in process BC , 200 J of heat is added to the system. The change in internal energy of the system in the process AB would be

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640 J

560 J

800 J

60 J

answer is A.

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Detailed Solution

No work is done along the path AB, because the process is isochoric.

$\begin{array}{l} ∴ Work done = P_{B} (V_{D} - V_{A}) \\ = 8 \times 10^{4} (5 \times 10^{- 3} - 2 \times 10^{- 3}) = 240 J \\ Q_{AC} = Q_{AB} + Q_{BC} = 600 + 200 = 800 J \\ ∴ (ΔU)_{AC} = Q - W = 800 - 240 = 560 J \end{array}$