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Q.

A thermodynamic process is shown in the following figure. In the process AB, 600J of heat is added to the system and in BC, 200J of heat is added to the system. The change in internal energy of the system in the process AC would be :
Given: $P_{A} = 3 \times 10^{4} P a, P_{B} = 8 \times 10^{4} p a, V_{A} = 2 \times 10^{- 3} m^{3}, V_{c} = 5 \times 10^{- 3} m^{3}$

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An Intiative by Sri Chaitanya

a

$560 J$

b

$800 J$

c

$600 J$

d

$640 J$

answer is A.

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Detailed Solution

In AB : 600 J heat is added

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In AB : 600 J heat is added
$q A B = 600 J, W_{A B} = 0 \Rightarrow 600 J$
For BC, 200 J heat is added
$W_{B C} = P_{B} (V_{C} - V_{B}) = P_{B} (V_{C} - V_{A}) = 8 \times 10^{4} (5 - 2) \times 10^{3} = 240 J q_{B C} + W_{B C} = Δ U_{B C} \Rightarrow Δ U_{B C} = 200 J - 240 J = - 40 J$

$Δ U_{A B} + Δ U_{B C} = Δ U_{A C}$ internal energy is state function

$\Rightarrow Δ U_{A C} = 560 J$

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