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A thermometer is graduated in millimeters. It registers –3 mm when the bulb of thermometer is in pure melting ice and 22 mm when the thermometer is in steam at a pressure of 1 atmosphere. The temperature in ^oC when the thermometer registers 13 mm is

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$\frac{13}{25} \times 100$

$\frac{16}{25} \times 100$

$\frac{13}{22} \times 100$

$\frac{16}{22} \times 100$

answer is B.

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Detailed Solution

$\frac{C - 0}{100 - 0} = \frac{13 - (- 3)}{22 - (- 3)} = \frac{16}{25}$

$\Rightarrow C = \frac{16}{25} \times 100$

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