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A thin balloon filled with air at 47°C has a volume of 3.0 litre. lf on placing it in a cooled room its volume becomes 2.7 litre, the temperature of the room is:

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30 °C

42 °C

0 ^oC

15 °C

answer is C.

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Detailed Solution

Here P = constant, so $V \propto T$ .
Therefore,

$∵ \frac{V_{2}}{V_{1}} = \frac{T_{2}}{T_{1}} \Rightarrow \frac{2.7}{3} = \frac{T_{2}}{320} \Rightarrow T_{2} = 288 K = 15^{o} C$

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