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A thin concavo-convex lens has two surfaces of radius of curvature $R$ and $2 R$ . The material of the lens has refractive index $μ .$ When kept in air, the focal length of the lens

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will be equal to $\frac{R}{μ - 1}$

will be equal to $\frac{2 R}{μ - 1}$

will depend on the direction from which light incident on it.

will be the same, irrespective of the direction from which light is incident on it.

answer is B, C.

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Detailed Solution

$\frac{1}{f} = (μ - 1) (\frac{1}{- 2 R} - \frac{1}{- R})$

$\Rightarrow \frac{1}{f} = (μ - 1) (\frac{1}{R} - \frac{1}{2 R})$

$\Rightarrow \frac{1}{f} = \frac{μ - 1}{2 R}$

$\Rightarrow f = \frac{2 R}{μ - 1}$

The focal length of lens has nothing to do with the direction from which the light is incident on it.

Hence, $(2)$ and $(3)$ are correct.

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