A thin conducting ring is ruptured, when it is given a charge q. Consider another thin conducting ring, radius of which is n times and tensile strength is k times of former ring (having same cross section).

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The given charge is non-uniformly distributed on the ring

The ring may contract or expand, based on the nature of charge given to it.

The given charge is distributed uniformly on the ring

The maximum charge, the second ring can be given without rupturing it is $< q n \sqrt{K}$ .

answer is A, C.

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Detailed Solution

Surface charge density is inversely proportional to radius of curvature for conducting surface. The electrostatic field deforms the ring, due to which reforming elastic forces are setup, and the ring attained equilibrium. The given charge resides on the surface of the ring.

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