A thin converging lens is placed between a fixed object and a screen. There are two positions of the lens for which a sharp image is formed on the screen. The height of one of the images is 2 cm while the magnification of the other image is 3. What is the height of the object?

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

9 cm

10 cm

6 cm

4 cm

answer is A.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

This is the lens displacement method. Given that magnification in 2nd case, m₂ = 3.

But, $m_{1} \times m_{2} = 1 \Rightarrow m_{1} = 1 / 3$

$m_{1} = \frac{size of 1^{st} image}{size of object}$

$\Rightarrow \frac{1}{3} = \frac{2}{h_{o}}$

$\Rightarrow h_{o} = 6 cm$

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test