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Q.

A thin converging lens is placed between a fixed object and a screen. There are two positions of the lens for which a sharp image is formed on the screen. The height of one of the images is 2 cm while the magnification of the other image is 3. What is the height of the object?

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a

6 cm

b

9 cm

c

10 cm

d

4 cm

answer is A.

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Detailed Solution

This is the lens displacement method. Given that magnification in 2nd case, m₂ = 3.

But, $m_{1} \times m_{2} = 1 \Rightarrow m_{1} = 1 / 3$

$m_{1} = \frac{size of 1^{st} image}{size of object}$

$\Rightarrow \frac{1}{3} = \frac{2}{h_{o}}$

$\Rightarrow h_{o} = 6 cm$

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A thin converging lens is placed between a fixed object and a screen. There are two positions of the lens for which a sharp image is formed on the screen. The height of one of the images is 2 cm while the magnification of the other image is 3. What is the height of the object?