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A thin disc of mass $M$ and radius ‘ $r$ ’ is rotating about its axis with a constant angular velocity $ω$ . Four objects each of mass $m$ , are kept gently to the opposite ends of two perpendicular diameters of the disc. The angular velocity of the disc will be:-

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$\frac{(M + 8 m) ω}{M}$

$\frac{(M + 8 m) ω}{M + 8 m}$

$\frac{M ω}{M + 8 m}$

$\frac{M ω}{4 m}$

answer is B.

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Detailed Solution

Applying conservation of angular momentum :

$ω' = \frac{M ω}{M + 8 m}$

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