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A thin equiconvex lens is made of glass of refrctiveindex 1.5 and its focal length is 0.2m. If it acts as a concave lens of 0.5 m focal length when dipped in a liquid, the refractive index of liquid is

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15/8

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answer is B.

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Detailed Solution

$\frac{f^{1}}{f} = \frac{(μ_{g} - 1)}{(\frac{μ_{g}}{μ_{1}} - 1)}; \frac{- 5}{2} = \frac{\frac{1}{2}}{(\frac{3}{2 μ_{1}} - 1)}; μ_{L} = \frac{15}{8}$

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