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Q.

A thin film is illuminated by wavelength 600nm in free space at nearly normal incidence. Calculate the min thickness of a thin film(μ=3/2)that results in constructive interference in the reflected light.

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a

600nm

b

300nm

c

100mm

d

100nm

answer is B.

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Detailed Solution

2μt=(2n+1)λ2n=0⇒232t=6002⇒t=100nm

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