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Q.

A thin hollow cylinder (opened at the both ends)of radius and length both equal to L. This object carries a uniform surface-charge density σ. The electrostatic potential at the point Ρ on the axis of the cylinder(as shown in the figure)comes out to be VP=σLkε0ln(1+h) Find the value of (k+h).

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answer is 4.

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Detailed Solution

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dq=2πLdxσ, dv=2πLσdx4πε0x2+L2

dv=σL2ε0OLdxx2+L2V=σL2ε0|ln(X+X2+L2|OL

V=σL2ε0[ln(L+L2)lnL], V=σL2ε0ln(1+2)

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