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Q.

A thin insulated tightly wound wire forms a plane spiral of N turns and carries current I. The radii of inside and outside turns are a and 3a respectively. Then magnetic field at the centre of spiral is μ0NInaIn(3) . Value of n is 

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answer is 4.

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Detailed Solution

dB=μ0In2rdB=μ0I2r×N2a×dr0BdB=μ0IN4aa3adrrB=μ0IN4a[lnr]a3aB=μ0IN4aln3

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