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Q.

A thin lens made of glass of refractive index 1.5 has a front surface + 11D power and back surface –6D. If this lens is submerged in a liquid of refractive index 1.6, the resulting power of the lens is

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a

– 0.5D

b

+0.5D

c

–0.625D

d

+0.625D

answer is C.

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Detailed Solution

Total power p = p1 + p2 = 11 − 6 = 5 DAlso f1fa =  aμg − 1 lμg − 1 ⇒ papl =  aμg − 1 lμg − 1⇒ 5p1 = 1.5 − 11.5 / 1.6 − 1 ⇒ pl = −0.625D

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