A thin liquid convex lens is formed in glass. Refractive index of liquid is 4/3 and that of glass is 3/2. If 'f' is the focal length of the liquid lens in air, its focal length and nature in the glass is

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f, convex

f, concave

2f, concave

3f, concave

answer is D.

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Detailed Solution

$\frac{f^{1}}{f} = \frac{(μ_{1} - 1)}{(\frac{μ_{1}}{μ_{g}} - 1)}; \frac{f^{1}}{f} = \frac{(\frac{4}{3} - 1)}{(\frac{\frac{4}{3}}{\frac{3}{2} - 1})} = - 3$

f'=-3f, the nature will be concave.

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