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A thin plane convex lens of focal length $f$ is split into two equal halves. One of the halves is shifted along the optical axis as shown. The separation between object and image planes is $1.8 m$ and the magnification of image formed by one of the half lens is $2$ . The separation between two halves is $d$ .

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$f = 0.6 m$

$f = 0.4 m$

$d = 0.6 m$

D=1.8m, $m_{1} = 2, m_{2} = \frac{1}{m_{1}} = \frac{1}{2}$

$f = \frac{D^{2} - d^{2}}{4 D} . . . . . . . . . (1) f = \frac{d}{m_{1} - m_{2}} . . . . . . . . . . (2) S o l v i n g, d = 0.6 m a n d f = 0.4 m$

answer is A, C.

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D = 1.8 m ,

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