A thin prism P1 with angle 4° and made from glass (μ = 1.54) is combined with another prism P2 made of another glass of μ = 1.72 to produce dispersion without deviation. The angle of prism P2 is

For no deviationμ1−1A1=μ2−1A24∘(1.54−1)=(1.72−1)A2A2=4×0.540.72=3∘

A thin prism P1 with angle 4° and made from glass (μ = 1.54) is combined with another prism P2 made of another glass of μ = 1.72 to produce dispersion without deviation. The angle of prism P2 is

For no deviationμ1−1A1=μ2−1A24∘(1.54−1)=(1.72−1)A2A2=4×0.540.72=3∘

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A thin prism P₁ with angle 4° and made from glass ( $μ$ = 1.54) is combined with another prism P₂ made of another glass of $μ$ = 1.72 to produce dispersion without deviation. The angle of prism P₂ is

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53.3°

4°

3°

2.6°

answer is C.

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For no deviation
$\begin{array}{l} (μ_{1} - 1) A_{1} = (μ_{2} - 1) A_{2} \\ 4^{\circ} (1 .54 - 1) = (1 .72 - 1) A_{2} \\ A_{2} = \frac{4 \times 0 .54}{0 .72} = 3^{\circ} \end{array}$

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A thin prism P1 with angle 4° and made from glass (μ = 1.54) is combined with another prism P2 made of another glass of μ = 1.72 to produce dispersion without deviation. The angle of prism P2 is

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A thin prism P₁ with angle 4° and made from glass ( $μ$ = 1.54) is combined with another prism P₂ made of another glass of $μ$ = 1.72 to produce dispersion without deviation. The angle of prism P₂ is