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A thin rectangular magnet suspended freely has a period of oscillation 4 s. If it is broken into two halves each having half their initial length, then when suspended similarly, the time period of oscillation of each part will be

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4 s

1 s

2 s

2 $\sqrt{2}$ s

answer is B.

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Detailed Solution

T ∝ $\sqrt{\frac{I}{M}}$

When length is halved, l will become $\frac{1}{8}$ times $(∵ I = \frac{m l^{2}}{12})$ while M will become half.

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