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A thin ring and a disc have same mass and roll without slipping with the same linear velocity v. If the total kinetic energy of the loop is 8 J, the kinetic energy of the disc must be

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16 J

4 J

6 J

8 J

answer is C.

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Detailed Solution

During rolling total KE of loop = ${mv}^{2} = 8 J$

Total KE of disc = $\frac{3}{4} {mv}^{2} = \frac{3}{4} 8 = 6 J$

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