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A thin rod AB of length 2m is moving with velocity V=3m/s in a uniform magnetic field of induction B=1.5 Tesla. Direction of velocity vector makes an angle of $θ = 30^{0}$ with the length of the rod. The P.D. between the ends of the rod is

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$V_{B} - V_{A} = 3 V$

$V_{B} - V_{A} = 4.5 V$

$V_{A} - V_{B} = 4 V$

$V_{A} - V_{B} = 4.5 V$

answer is A.

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$P . D = Blvsin θ$

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