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Q.

A thin rod of length f/3 lies along the axis of a concave mirror of focal length f. One end of its magnified image touches an end of the rod. The length of the image is

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a

f/2

b

2f

c

f/4

d

f

answer is B.

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Detailed Solution

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solution

As one end image and object coincide that object distance must be 2f

other end distance 2f-f/3=5f3

Applying mirror equation 1v-35f=-1f v=5f2

so image size=5f/2-2f=f/2

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