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Q.

A thin rod of mass ‘m’ and length 2L is made to rotate about a normal axis through centre of rod. If its angular velocity changes from ‘O’ to ‘ω’ in time ‘t’. The torque acting on it is

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a

mL2ω/12t

b

mL2ω/3t

c

4mL2ω/3t

d

mL2ω/t

answer is B.

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Detailed Solution

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τ=dLdt==Iωt; I=m(2L)212 τ=m4L2ω12t; τ=mL2ω3t

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