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Q.

A thin uniform rod AB of mass 1.0 kg makes translationally motion with acceleration 2.0 m / s2 due to two anti-parallel force F1 and F2 . The distance between the point at which these forces are applied is equal to a = 20 cm. Besides, it is known that F2 = 5.0N . Find the length of the rod in m. 

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a

3 m

b

2 m

c

1 m

d

1 cm

answer is C.

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Detailed Solution

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a=F2-F1m⇒2=5-F11

F1=3N

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Sum of moments about C.M is zero

F1(a+x)=F2×x⇒3(0.2+x)=5×x

⇒x=0.3

length of the rod is 2(a+x) = 1m

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