A thin walled glass container is filled with water $(μ = \frac{4}{3})$ . A point source $S$ is fixed inside water. A thin equiconvex lens ( $µ = 1.5$ ) and concave mirror are arranged with mutual separation $\frac{R}{2}$ as shown in figure.
The distance of lens from the plane surface of the container is also $\frac{R}{2}$ for first (as shown in diagram) and $\frac{R}{6}$ for second question of the stem (assume suitable change in diagram). Here R is radius of curvature of all curved surfaces. An observer is present at the position of $S$ itself. The distance of $S$ from A is $mR$ , and separation between final image seen by observer and observer himself is $nR$ .

Question

A thin walled glass container is filled with water $(μ = \frac{4}{3})$ . A point source $S$ is fixed inside water. A thin equiconvex lens ( $µ = 1.5$ ) and concave mirror are arranged with mutual separation $\frac{R}{2}$ as shown in figure.
The distance of lens from the plane surface of the container is also $\frac{R}{2}$ for first (as shown in diagram) and $\frac{R}{6}$ for second question of the stem (assume suitable change in diagram). Here R is radius of curvature of all curved surfaces. An observer is present at the position of $S$ itself. The distance of $S$ from A is $mR$ , and separation between final image seen by observer and observer himself is $nR$ .

Infinity Learn · Accepted Answer

AI1=ASμ=2R3×43=R/2focal length of lens 1fl=(1.5−1)1R+1Rf1 = R, focal length of mirror fm = R/2i.e., I1 is at focus of lens, so rays coming from I1 gets parallel after passing through lens and they are again reflected by mirror which forms image at optical centre of lens (focus of mirror)Now there is one more refraction at AB and final image is at R/2. 4/3= 2R/ 3 from A, so. 4R/3 from S.

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