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A thin wire is bent in the form of a ring of diameter $3.0 cm$ . The ring is placed horizontally on the surface of soap solution and then raised up slowly. Upward force necessary to break the vertical film formed between the ring and the solution is

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$6 πT$ dyne

$2 πT$ dyne

$3 πT$ dyne

$4 πT$ dyne

answer is A.

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Detailed Solution

From two surfaces,

A thin wire is bent in the form of a ring of diameter 3.0cm.The ring is placed horizontally on the surface of soap solution and then raised up slowly. Upward force necessary

$F = 2 (Tl) = 2 (T) (2 πr) = 2 (T) (2 π) (1.5) = (6 πT) dyne$

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