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A thin wooden stick of length 5 cm is floating on water. Surface tension of water is 0.07 Nm^-1. If a hot needle is placed on one side of the stick, surface tension decreased to 0.06 Nm^-1. Now the net force on the stick is

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zero

0.1 N

0.001 N

0.0005 N

answer is D.

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Detailed Solution

$F = (T_{1} - T_{2}) l = (0.07 - 0.06) \times 5 \times 10^{- 2} N$

$= 5 \times 10^{- 4} N$

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