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Q.

A time dependent force F = 3t2 + 6t acts on a particle of mass 18 kg. If particle starts from rest, the work done by the force during the first 3 second, will be : 

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a

40.5 J

b

324 J

c

81 J

d

262 J

answer is C.

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Detailed Solution

Change in momentum 
ΔP=Fdt ΔP=033t2+6tdt=54

P0=54,P=54ΔK=P22m=54×542×18=81 Joule 

 

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