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Q.

A toroidal solenoid has 3000 turns and a mean radius of 10cm. It has a soft iron core of relative permeability 2000. Find the magnetic field in the core when a current of 1.0A is passed through the solenoid. (in T)

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answer is 12.

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Detailed Solution

$B = μ_{r} μ_{0} (\frac{N}{2 πr}) I \Rightarrow B = 2000 \times 4 π \times 10^{- 7} \times \frac{3000}{2 π \times 0 .1} \times 1 \Rightarrow B = 12 T$

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