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Q.

A toroidal solenoid has 3000 turns and a mean radius of 10 cm. It has a soft iron core of relative permeability 2000. What is the magnitude of the magnetic field in the core when a current of 1 A is passed through the solenoid?

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a

0.12 T

b

12 T

c

1.2 T

d

0.012 T

answer is D.

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Detailed Solution

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The magnetic field in the core is given by B=μnI

When μ is the permeability of soft iron and n is the number of turns per unit length of the solenoid. 

Now μr=μμ0 and n=30002πr=30002π×0.1

B=μrμ0nI=2000×4π×107×30002π×0.1×1=12T

Hence the correct choice is (d)

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