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A total charge Q is broken in two parts Q₁and Q₂ and they are placed at a distance R from each other. The maximum force repulsion between them will occur when:

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$Q_{2} = \frac{Q}{3}, Q_{1} = Q - \frac{Q}{3}$

$Q_{2} = \frac{Q}{4}, Q_{1} = Q - \frac{2 Q}{3}$

$Q_{2} = \frac{Q}{4}, Q_{1} = Q - \frac{3 Q}{3}$

$Q_{1} = \frac{Q}{2}, Q_{2} = \frac{Q}{2}$

answer is D.

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Detailed Solution

F= $\frac{K Q_{1} (Q - Q_{1})}{R^{2}}$

Force is maximum if
$\frac{dF}{{dQ}_{1}} = 0 \Rightarrow Q_{1} = Q_{2} = \frac{Q}{2}$

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