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A tower is 100 m high, what will be the angle of elevation, from a point 100 m away from its foot, to the top of the tower?

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90 °

30 °

60 °

45 °

answer is C.

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Detailed Solution

We are given a tower that is 100 m high and a point 100 m away from the base of the tower.
Let ‘

θ

’ be the angle of elevation.
Question Image

We know,

tanθ = \frac{Perpendicular}{Base}

\tan 45 ° = 1

In triangle ACB,

tan θ = 100100 ⇒ tan θ = 1 ⇒ θ = 45 °

Thus the angle of elevation is

45^{\circ}

.
Thus, option 3 is correct.

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