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Q.

A tower is 100 m high, what will be the angle of elevation, from a point 100 m away from its foot, to the top of the tower?

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a

   90 °  

b

   30 °   

c

   60 °  

d

   45 °  

answer is C.

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Detailed Solution

We are given a tower that is 100 m high and a point 100 m away from the base of the tower.
Let ‘ θ   ’ be the angle of elevation.
Question ImageWe know,
tanθ=PerpendicularBase
tan45°=1
In triangle ACB,
  tanθ = 100 100 ⇒tanθ =1 ⇒θ = 45 °  
Thus the angle of elevation is 45∘.
Thus, option 3 is correct.
 
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