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A train 240 m long is running with a speed of 48 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?

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Detailed Solution

Distance = 240

$S_{1} = 48 k m p h$

$S_{2} = 6 k m p h$

$∴ B o t h a r e s a m e d i r e c t i o n relative s p e e d = S_{1} + S_{2}$

$= 48 + 6 = 54 k m p h$

$= 54 \times \frac{5}{18} = 15 m / \sec$

$T = D / S = \frac{240}{15} = 16 \sec$

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