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Q.
A train approaches tunnel A B. Inside the tunnel is a cat located at a point that is of the distance A B measured from the entrance
. When the train whistles, the cat runs. If the cat moves to the entrance of tunnel
The train catches the cat exactly at the entrance. If the cat moves to the exit
The train catches the cat exactly at the exit. The speed of the train is greater than the speed of the cat by what order ?
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a
3: 1
b
4:1
c
5: 1
d
None of these
answer is B.
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Detailed Solution
Concept- To answer this question, we must first create an abstract mental image, which we then sketch to make the topic more comprehensible. The equations for two situations (depending on the movement of the cat) will then be framed using the formulae, and by doing more calculations, we will approach our solution.
Let x be the distance between the train and the tunnel entrance when the train whistles, and let AB be the length of the tunnel.
Let the train and cat go at speeds of T and C, respectively.
Here
is the distance covered by cat and
is the speed of cat while moving towards
which calculates the time taken by cat to reach
. It will be equal to the time taken by train to reach
as the train and cat meet at
and
is the distance covered by the train and
is the speed of the train.
Similarly when the train is moving towards
, it will cover
distance at the speed of
which will calculate time which will be equal to time taken by cat while covering
distance at the speed of
.
When the cat moves Towards the Entrance A,
Cat moving towards the Entrance B,
_______(2)
On Dividing Equation (1) by Equation (2) we get

Putting value of
in Eq (1) we get

Hence, the correct answer is option 2.
Let the train and cat go at speeds of T and C, respectively.
Here
Similarly when the train is moving towards
When the cat moves Towards the Entrance A,
On Dividing Equation (1) by Equation (2) we get
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