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A train has to negotiate a curve of radius 400 m. By how much height should the outer rail be raised with respect to inner rail for speed of 48 km/h? The distance between the rails is 1 m

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3.3 cm

4.4 cm

9 cm

2.2 cm

answer is A.

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Detailed Solution

v= 72 km/h = 72 $\times \frac{5}{18}$ m/s = 13.33

tan $θ$ = $\frac{v^{2}}{R g}$ = 0.044

0.044= $\frac{h}{1}$

h= 0.044 m =4.4 cm

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