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A train is moving at a speed of $40 km/h$ at 10.00 a.m and at 50 km/h at 10.15 a.m. Assuming that the train moves along a straight track and the acceleration is constant, find out the value of the acceleration.

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25 {km/h}^{2}

30 {km/h}^{2}

35 {km/h}^{2}

40 {km/h}^{2}

answer is B.

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Detailed Solution

Acceleration = \frac{Change ​ in ​ speed}{Time taken}

$= \frac{50-40}{15min} = \frac{10 kmph}{\frac{1}{4} h} = 40 \frac{km}{h^{2}}$

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