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A train is travelling at a speed of $90 km / h$ . Brakes are applied so as to produce a uniform acceleration of $- 0.5 m / s²$ . Then how far will the train go before it is brought to rest__ $m$ ?

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526

180

625

720

answer is C.

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Detailed Solution

A train is travelling at a speed of

90 km / h

. Brakes are applied so as to produce a uniform acceleration of

- 0.5 m / s²

. The train goes before it is brought to rest would be

625 m

.
Given:

u = 90 km / h

= 90 \times (\frac{5}{18})

= 25 m / s,

a = - 0.5 m / s², v = 0

.
Formula:

v² - u² = 2 aS

Putting all the values we get,
⇒

0 - 625 = 2 \times (- 0.5) \times S

⇒

S = 625 m

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