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A train is travelling at a speed of 90kmph brakes are applied so as to produce a uniform acceleration of $- 0.5 {ms}^{- 2}$ . Then how much distance will
train take to come to rest is

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560 m

625 m

725 m

800 m

answer is B.

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Detailed Solution

$u = 90 kmph$

$=90× \frac{5}{18} = 25 m/s$

$a = - {0.5m/s}^{2} s = ?$

$v^{2} - u^{2} = 2 as$

$- {(25)}^{2} = - 2 \times 0.5 \times S$

$S = 625 m$

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