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Q.

A train is travelling with a speed of 72kmph. The driver applies brakes so that a uniform acceleration of −0.2 ms−2is produced. The distance travelled by the train before it comes to rest is        

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a

1 km

b

10 km

c

0.1 km

d

0.01 km

answer is A.

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Detailed Solution

Initial velocityu=72kmph=72×518=20m/s

Accelerationa=−0.2ms−1, Final velocity v = 0

We know v2−u2=2as

⇒(0)2−(20)2=2(−0.2)×s

s=1000m⇒s=1km

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