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Q.

A train moving with a uniform acceleration, crosses station A with a velocity of

108kmph and another station B with a velocity of 144kmph. The time taken for the train to travel from A to B is 20 minutes.  The distance between the two stations is                                 

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a

40 km

b

24 km

c

42 km

d

32 km

answer is B.

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Detailed Solution

Initial velocity u = 108kmph

Final velocity v = 144kmph

Time taken (t) = 20 minutes =13hr

Distanced travelleds=(u+v2)×t=(108+1442)×13=42km

s=42km

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