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A train starting from a railway station and moving with uniform acceleration attains a speed of $40 km / h$ in $10 minutes$ . What is its acceleration?

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- 0.0185 m / s²

0.0185 m / s²

0.0185 km / h²

- 0.0185 km / h²

answer is B.

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Detailed Solution

The acceleration is

0.0185 m / s²

.
Initial speed of the train,

u = 0 km

. (Because the train starts from the rest)
Final speed of the train,

v = 40 km / h

= (5 / 18) \times 40

= 11.11 m / s

.
Time taken to attain the speed

= 10 minutes

= 10 \times 60

= 600 \sec

.
Acceleration

= a

.
Formula:

a = \frac{(v - u)}{t}

Putting the values, we get

a = \frac{(11.11 - 0)}{600}

= 0.0185 m / s²

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