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A train starting from rest attains a velocity of $72 km / h$ in $5 \min$ . Assuming that the acceleration is uniform, the acceleration of the train is

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3 m / s^{2}

4.5 m / s^{2}

1 / 15 m / s^{2}

2 m / s^{2}

answer is C.

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Detailed Solution

A train starting from rest attains a velocity of

72 km / h

5 \min

. Assuming that the acceleration is uniform, then the acceleration is

1 / 15 m / s^{2}

Given
Initial velocity of train,

(u) = 0

(since the train starts from the rest)
Final velocity of train

(v) = 72 km / h

= 72 \times \frac{5}{18} m / s

= 20 m / s

Time (t) = 5 \min

= 300 \sec

By the equation of motion, acceleration will be _

v = u + at

Putting values;

\Rightarrow 20 = 0 + a \times 300

\Rightarrow a = \frac{20}{300}

\Rightarrow a = \frac{1}{15} m / s^{2}

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