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A train starting from rest attains a velocity of $90 km / hr$ in $2 minutes$ . Then the distance travelled by the train to attain this velocity is

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1.5 km

2 km

2.5 km

1.2 km

answer is A.

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Detailed Solution

A train starting from rest attains a velocity of

90 km / hr

2 minutes

. Then the distance travelled by the train to attain this velocity is

1.5 km

.
Given:
Initial velocity

u = 0 km / h

Final velocity

v = = 90 km / h

Time taken

t = 2 \min

= > t = 2 / 60 h

= > t = 1 / 30 h

Acceleration

a = ?

a = \frac{v - u}{t}

= > a = \frac{90 - 0}{\frac{1}{30}}

= > a = 2700 km / h^{2}

The distance travelled by the train can be calculated using the second equation of motion as follows:

s = ut + \frac{1}{2} a t^{2}

= > s = 0 + \frac{1}{2} \times 2700 \times (\frac{1}{30})^{2}

= > s = 1.5 km

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