A Train travels at two speeds $40\mathit{ km}/h$ and $46.67\mathit{ km}/h$ during its whole journey. It travels a distance of “$x$” km at $30\mathit{ km}/h$ in one hour and a distance of “$y$” km at $46.67\mathit{ km}/h$ in $1.5$ hours. The value of $x$ and y is $30$ $\mathit{km}$ and _______$\mathit{ km}$ and value of average speed is ________ $\mathit{km}/h$.

A Train travels at two speeds $40\mathit{ km}/h$ and $46.67\mathit{ km}/h$ during its whole journey. It travels a distance of “$x$” km at $30\mathit{ km}/h$ in one hour and a distance of “$y$” km at $46.67\mathit{ km}/h$ in $1.5$ hours. The value of $x$ and $y$ is $30\mathit{ km}$ and $70\mathit{ km}$ and value of average speed is $40\mathit{ km}/h$.
Speed =  $\frac{\mathit{Distance}}{\mathit{Time}}$
It is given that train travels a distance of “$x$” kilometre at $30\mathit{ km}/h$ in one hour and a distance of “y” km at $46.67\mathit{ km}$ in $1.5$ hours
∴ $30=\frac{x}{1}$
$\Rightarrow \mathit{ x}=30\mathit{ km}$      ……….(1)
and $46.67=\frac{y}{1.5}$
$\Rightarrow \mathit{ y}=70\mathit{ km}$     ………..(2)
Now,
Average speed $=\frac{\mathit{Total\; distance\; travelled}}{\mathit{Total\; time\; taken}}$
Total distance travelled $=30+70$
                                      $=100\mathit{ km}$
Total time taken $=1+1.5$
                           $=2.5 h$
Average speed $=\frac{100}{2.5}$
                        $=40\mathit{ km}/h$