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Q.

A transformer consisting of $300$ turns in the primary and $150$ turns in the secondary gives output power of $2.2 k W$ . If the current in the secondary coil is $10 A$ , then the input voltage and current in the primary coil are

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a

440 V and 20 A

b

440 V and 5 A

c

220 V and 10 A

d

220 V and 20 A

answer is B.

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Detailed Solution

Given:

$N_{i} = 300, N_{0} = 150 P_{0} = 2.2 k W = 2.2 \times 10^{3} W = 2200 W, I_{0} = 10 A ∵ P_{0} = V_{0} I_{0} \Rightarrow 2200 = V_{0} \times 10 \Rightarrow V_{0} = 220 V ∵ \frac{V_{i}}{V_{0}} = \frac{N_{i}}{N_{0}} \Rightarrow V_{i} = \frac{N_{i}}{N_{0}} V_{0} = \frac{300}{150} \times 220 = 440 V A l s o, P_{0} = V_{i} I_{i} \Rightarrow I_{i} = \frac{P_{0}}{V_{i}} = \frac{2200}{440} = 5 A$

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