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Q.

A transformer having efficiency of 90% is working on 200 V and 3 kW power supply. If the current in the secondary coil is 6 A, the voltage across the secondary coil and the current in the primary coil respectively are

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a

450 V, 15A

b

600 V, 15A

c

450 V, 13.5A

d

300 V, 15A

answer is B.

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Detailed Solution

$I_{P} = \frac{P_{I}}{V_{P}} = \frac{3000}{200}$

$P_{o} = P_{I} \times \frac{90}{100}$

$= 3000 \times \frac{90}{100} = 2700 W$

$V_{Q} = \frac{P_{0}}{I_{S}} = \frac{2700}{6} = 450 V$

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