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A transformer is used for a 100 watt, 20 volt electric bulb at a place where the A.C. mains potential is 200 volt and the current drawn is 0.6 A. The efficiency of the transformer is nearly :

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48%

30%

83%

68%

answer is D.

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Detailed Solution

Percentage efficiency = $\frac{V_{s} I_{s}}{V_{p} I_{p}} x 100 = \frac{100}{200 x 0.6} x 100 = 83 %$

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