A transformer operating at primary voltage 8kV and secondary voltage 160V serves a load of 80kW. Assuming the transformer to be ideal with purely resistive load and working on unity power factor, the loads in the primary and secondary Circuit would be

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10 $Ω$ and 500 $Ω$

1.06 $Ω$ and 500 $Ω$

800 $Ω$ and 0.32 $Ω$

800 $Ω$ and 1.06 $Ω$

answer is C.

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Detailed Solution

$\begin{array}{l} P = \frac{V^{2}}{R} \\ 80 \times 10^{3} = \frac{{(8 \times 10^{3})}^{2}}{R_{i}} \\ R_{i} = 800 Ω \\ P_{0} = 80 kw = \frac{160^{2}}{R_{0}} \\ R_{0} = 0.32 Ω \end{array}$

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