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Q.

A transformer with efficiency 80% works at 4 kW and 100 V. If the secondary voltage is 200 V, then the primary and secondary currents are respectively.

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a

20A and 90A

b

16A and 40A

c

40A and 20A

d

40A and 16A

answer is A.

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Detailed Solution

$P_{1} = V_{1} I_{1} \Rightarrow I_{1} = \frac{4 \times 10^{3}}{100} = 40 A$

$P_{2} = \frac{80}{100} \times 4 \times 10^{3} W = 3200 W$

$I_{2} = \frac{3200}{200} A = 16 A$

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