A transistor connected in common emitter configuration has input resistance $R_{B} = 2 k Ω$ and load resistance of $5 k Ω$ . If $β = 60$ and an input signal 12mV is applied, calculate the voltage gain, the power gain and the value of output voltage

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

A_v=150, V_out=1.8V, and power gain=9000

A_v=20, V_out=1V, and power gain=2000

A_v=150, V_out=1.5V, and power gain=8500

A_v=20, V_out=1.5V, and power gain=2000

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$A_{r} = \frac{R_{0}}{R_{i}} = \frac{5}{2} = 2.5$

$A_{v} = β \cdot \frac{R_{0}}{R_{i}} = 60 \times 2.5 = 150$

$A_{p} = A_{v} \times β = 150 \times 60 = 9000$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE