A transistor is connected in common emitter configuration. The collector supply is 8V and the voltage drop across a resistance of $800 Ω$ in the collectror circuit is 0.5 V. If the current gain factor $α$ is 0.96, then the base current is

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$2.6 \times 10^{- 5} A$

$3.6 \times 10^{- 5} A$

$5.6 \times 10^{- 5} A$

$6.6 \times 10^{- 5} A$

answer is A.

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Detailed Solution

$\frac{1}{β} = \frac{1}{α} - 1 \Rightarrow β = 24$

$β = \frac{Δ I_{C}}{Δ I_{B}} \Rightarrow 24 = \frac{0.5}{800 I_{B}}$

$\Rightarrow I_{B} = 2.6 \times 10^{- 5} A$

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